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DOE-HDBK-3010-94
7.0 Application Examples; Liquid Storage and Ion Exchange Examples
11,650 g * 1.0 * 2E-4 * 0.5 = 1.2 g
If all process tanks are full at their flowsheet parameters, the MAR is 42 kg. The
free-fall spill of all this material produces an initial airborne source term of:
(7920 g * 1.0 * 2E-5 * 1.0) + (34,960 g * 1.0 * 2E-4 * 0.5) = 3.7 g
A pipe or tank failure that resulted in the release of a pressurized spray due to pump
pressure, would produce the same release as free-fall spill for the lower density
solutions (i.e. < 1.2 g/cm3), and a greater release for the high-density solutions.
This scenario would be similar to the spray leak examined for the metal dissolver in
subsection 7.3.4.2. The physical phenomena is depressurization of liquid via a failure
under the liquid surface level, for which the ARF and RF are 1E-4 and 1.0
(subsection 3.2.2.3.1). If the spray failure occurs for one of the high density ion
exchange feed tanks, the initial airborne source term is:
1320 g * 1.0 * 1E-4 * 1.0 = 0.1 g.
The free-fall spill release for the high-density solution is only 0.03 g.
B. Large Room Fire. There is no obvious mechanism for postulating a large room
fire in the maintenance side of the wet processing line, but one is postulated from an
undefined source. Unlike the previous case where an undefined large fire was
postulated (Feed Preparation example, section 7.3.1), it will cause a significant
increase in source term for the process. The principle mechanisms for release are
boiling of liquid and release of superheated liquid.
Before estimating releases, it is appropriate to consider the type of fire that would
significantly affect the stored liquid. The precipitator feed tanks (13 and 14) have
both the largest plutonium (11,650 g) and smallest liquid inventories (130 l). The
heat required to boil and vaporize this solution is estimated assuming the
thermodynamic properties of water, the density of the nitric acid solution, and an
initial temperature of 30 oC. The sensible heat needed to raise the temperature to
boiling is:
130 l * 1000 cm3/l * 1.3 g/cm3 * 1 cal/g oC * (70 oC) = 1.2E+7 calories
The latent heat needed to vaporize the solution is:
130 l * 1000 cm3/l * 1.3 g/cm3 * 539 cal/g = 9.1E+7 calories
Page 7-30


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